(x^2-x)/2=1/8

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Solution for (x^2-x)/2=1/8 equation: 


x in (-oo:+oo)

(x^2-x)/2 = 1/8 // - 1/8

(x^2-x)/2-(1/8) = 0

(x^2-x)/2-1/8 = 0

(8*(x^2-x))/(2*8)+(-1*2)/(2*8) = 0

8*(x^2-x)-1*2 = 0

8*x^2-8*x-2 = 0

8*x^2-8*x-2 = 0

2*(4*x^2-4*x-1) = 0

4*x^2-4*x-1 = 0

DELTA = (-4)^2-(-1*4*4)

DELTA = 32

DELTA > 0

x = (32^(1/2)+4)/(2*4) or x = (4-32^(1/2))/(2*4)

x = (4*2^(1/2)+4)/8 or x = (4-4*2^(1/2))/8

2*(x-((4-4*2^(1/2))/8))*(x-((4*2^(1/2)+4)/8)) = 0

(2*(x-((4-4*2^(1/2))/8))*(x-((4*2^(1/2)+4)/8)))/(2*8) = 0

(2*(x-((4-4*2^(1/2))/8))*(x-((4*2^(1/2)+4)/8)))/(2*8) = 0 // * 2*8

2*(x-((4-4*2^(1/2))/8))*(x-((4*2^(1/2)+4)/8)) = 0

( 2 )

2 = 0

x belongs to the empty set

( x-((4*2^(1/2)+4)/8) )

x-((4*2^(1/2)+4)/8) = 0 // + (4*2^(1/2)+4)/8

x = (4*2^(1/2)+4)/8

( x-((4-4*2^(1/2))/8) )

x-((4-4*2^(1/2))/8) = 0 // + (4-4*2^(1/2))/8

x = (4-4*2^(1/2))/8

x in { (4*2^(1/2)+4)/8, (4-4*2^(1/2))/8 }

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